(1/6)^3x+2=36

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Solution for (1/6)^3x+2=36 equation: 



(1/6)^3x+2=36

We move all terms to the left:

(1/6)^3x+2-(36)=0



Domain of the equation: 6)^3x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/6)^3x+2-36=0

We add all the numbers together, and all the variables

(+1/6)^3x-34=0

We multiply all the terms by the denominator


(+1-34*6)^3x=0

We add all the numbers together, and all the variables

(-203)^3x=0

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